How do you find the energy of a photon?
To figure out the energy, we use the E = hf equation. The energy of each photon is equal to Planck’s constant, multiplied by the frequency of the light, h is always 6.63 * 10^-34 Joule seconds, and the frequency is 6 * 10^14 Hz. Plug those in and solve, and we get 4 * 10^-19 Joules.
What is the energy of a photon with a a wavelength of 827 nm what type of radiation is it?
What type of radiation is this? a) a wavelength of 827 nm? What type of radiation is it? E=ho hc (6.63×10 -34) (3.00 x 108) na 2 = 2.41810-19 J 5.
What is the energy of green light of the stoplight wavelength of light 532 nm 6.626 10 34 JSE HF?
2 Answers. The answer is 3.54×10−19 J . The equation for determining the energy of a photon of electromagnetic radiation is E=hν , where E is energy in Joules, h is Planck’s constant, 6.626×10−34J⋅s , and ν (pronounced “noo”) is the frequency.
What is the energy of a photon with a wavelength of 400.0 nm?
3.1 eV
Solution: From the previous problem, the energy of a single 400 nm photon is 3.1 eV.
What is the energy of one photon?
The energy of a single photon is: hν or = (h/2π)ω where h is Planck’s constant: 6.626 x 10-34 Joule-sec. One photon of visible light contains about 10-19 Joules (not much!)
What is the energy of a photon with a wavelength of 500 nm?
The energy of a 500 nm photon is 4 x 10^-19 J.
How do you find the energy of a photon given the wavelength?
Similarly, if the wavelength of the photon is known then the energy of the photon can be calculated using the formula E=hc/λ. In the equation, h is the Planck’s constant, c is the speed of light and λ the wavelength of the radiation.
What is the energy of a photon of yellow light whose wavelength is 589 nm?
Calculate the energy of one photon of yellow light whose wavelength is 589 nm. ) = 3.37 x 10-19 J.